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Part E Now assume that the pitcher in Part D throws a o 165 kg baseball parallel

ID: 778807 • Letter: P

Question

Part E Now assume that the pitcher in Part D throws a o 165 kg baseball parallel to the ground with a speed of 19.0 m/s in the -x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line What is the ball's x-component of velocity just after leaving the bat if the bat applies an impulse of +6.9 N-s to the baseball? Enter your answer numerically in meters per second using two significant figures. 60.8182 Submit X Incorrect; Try Again; 5 attempts remaining m/s V. = Previous Answers Request Answer

Explanation / Answer

Impulse = change in momentum

dp = m(v2 - v1)

6.9 = 0.165*(v2 - 19)

v2 = 60.81 m/s

so please try with value 61 m/s as the answer

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