B Y Y D 5 pt (8e27p73) A controler on a electronic arcade game con hists of a va

Question

B Y Y D 5 pt (8e27p73) A controler on a electronic arcade game con hists of a variable resistor connected across the plates of a 0.190 F capacitor. The capacitor is charged to 4.50 V, then 17 discharged through thhe resistor. The time for the potential (in A) difference across the plates to decrease to 0.800 V is sured by a clock inside the game can be handlee range of discharge 12. AO -213 x10 BO -26710 CO-333 10 ms, what should be the resistance range of the resistor? Low end resistance? (in ohns) GO -814x 10- HO-1.02 10.AQIS7x10' BO2.11xo' ios Pt]Calculate Va.. (in V) 13. AO 218 : c02.39 CO 3.41 FO 6.67 GO 3.89 x 10 HO 4.40 x 10 DO 427 GO 8.33 BO 2.73 EO 5.33 HO 1.04 x 10 5 pt High-enid resistance? (in ohms) 11. AO 2.48 10 BO 3.30x 10 CO 439 x 10 DO 5.84 x 10 EO 7.77 x 10" FO 1.03 x 10 GO 1.37 k 10 HO 1.83 x 10 5 pt R1 a R1 R2 motor Lights C2 R1 (c28p38) When the lights of an automobile are switched on, an ammeter in series with them reads 9.9 A and a voltmeter connected across them reads 11.80 V. See the figure. When the electric starting motor is turned on, the ammeter reading drops to 7.7 A and the lights dim soanwhat. If the internal Assume that R1-5.0 , R2-10.0 , e: 4.0 V, and G- e3-8.0 . Take positive current as that flowing through the battery from - to +. (a) Calculate the current through each ideal battery in the figure resistance of the battery is 0.058 12 and that of the ammeter is negligible, what is the emf of the battery when the lights are on? (in V) 14. AO 6.60 BO 7.73 CO 9.04 DO 1.06 x 10 EO 124x 10 FO 1.45x10 GO 1.69 x 10 HO 1.98 x 10

Explanation / Answer

Q10.

capacitance=C=0.19 uF

initial voltage=V=4.5 volts

final voltage=0.8 volts

let time taken be t seconds and time constant be T.

then using the exponential decrease law,

0.8=4.5*exp(-t/T)

==>t/T=1.7272

as t varies from 10 us to 6 ms,

T will vary from 5.7896 us to 3.4738 ms

time constant =R*C

then low end resistance=5.7896 us/0.19 uF=30.472 ohms

hence option E is correct.

part 2:

high end resistance=3.4738 ms/0.19 uF=1.8283*10^4 ohms

option H is correct.

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