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. 1. The work done by the magnetic force (Fqx Bydue to uniform magnetic field B

ID: 778433 • Letter: #

Question

. 1. The work done by the magnetic force (Fqx Bydue to uniform magnetic field B on a charge q moving with velocity is (a)Zero (b) gB.(o) (e) gor B (so) (d) none of them 2 What happens to an electron placed at rest (no initial velocity) in a magnetic field ? (a) starts to move in a circle with coustant speed as magnetic force is always perpendicular to velocity (b) start to move at constant acceleration due to magnetic force (c) starts to move with constant velocity (d) none of the above 3. What will be the magnetic field's direction at point P for the two currents shown in figure 1? (a) left to right (b) right to left(e) up (d) down fa

Explanation / Answer

1. Option (a) is correct work done will be zero because angle between force and displacement is 900

2. Option (d)

Since velocity is zero hence there isn't any force acting on him.

3. Option (d)

downward by using right hand curl rule.