(32%) Problem 2: The magnetic field of a proton is relatively close to that of a

Question

(32%) Problem 2: The magnetic field of a proton is relatively close to that of a circular current loop 0.650 x 10 15 m in radius carrying 1.05 x 10t A. An MRI machine is required to be able to manipulate these fields. 50% Part (a) To see why an MRI utilizes iron to increase the magnetic field produced by a coil, calculate the current required in a 400 loop-per-meter circular coil 0.660 m in radius to produce a 1.20 T field (typical of an MRI instrument) at its center with no iron insert. Grade Summary Deductions 12% Potential 88% sin0 tan() | | ( coso cotan)asi acos0 Submissions Attempts remaining: 6 3% per attempt) atan acotan)sin 2 3 detailed view cosh tan cotanh0 Degrees O Radians 39% 3% 396 396 Submit Hint Hints: 1% deduction per hint. Hints remaining:- Feedback: 0% deduction per feedback.

Explanation / Answer

Magnetic field inside a solenoid (coil) B = o  nI where n is the number of turns per unit length

and I is current.

1.2 = 4 x 10-7 x 400 x I

I = 2387.324 Amperes

So, 2387.324 Amperes of current is needed

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