(10%) Problem 4: An electron in a TV CRT moves with a speed of 6.75 × 107 m/s, i
ID: 777974 • Letter: #
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(10%) Problem 4: An electron in a TV CRT moves with a speed of 6.75 × 107 m/s, in a direction perpendicular to the Earth's magnetic field, which has a strength of 4.75 x 10-5 T. 50% Part(a) What electric field strength in kV/m must be applied perpendicular to the Earth's magnetic field to make the electron moves in a straight line? Grade Summary Potential Submissions 100% cos(O) 789 sin cotan atan)a tan() | | ( acosO Attempts remaining: I0 asin % per attempt) detailed view acotansinh0 cosh0nh0 cotanh0 Degrees Radians 0 END BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 1 % deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 50% Part(b) If this is done between plates separated by 0 85 cm what is the voltage applied in V? (Note that TVs are usually surrounded by a ferromagnctic material to shicld against external magnctic ficlds and avoid the need for such a correction.)Explanation / Answer
a) magnetic force = electric force
qVB = qE
E = VB = 6.75*10^7*4.75*10^-5 = 3.2*10^3 N/C
b) V = E*d
=3.2*10^3*0.0085 = 27.25 Volts
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