Question 3-7 includilg f Solve the following problems. Show all work circle or b

Question

Question 3-7 includilg f Solve the following problems. Show all work circle or box your final answer friends find themselves getting a workout. They apply a cumulative force of 1080 N to push the car 218 m to the nearest fuel station. Determine the work done on the car. 1) Renatta Gass is out with her friends. Misfortune occurs and Renatta and her 2) Hans Full is pulling on a rope to drag his backpack to school across the ice. He pulls upwards and rightwards with a force of 22.9 Newtons at an angle of 35 degrees above the horizontal to drag his backpack a horizontal distance of 129 meters to the right. Determine the work (in Joules) done upon the backpack. 3) Deadlifting involves raising a loaded barbell from the floor to a position above the head with outstretched arms. Determine the work done by Lamar in deadlifting 300 kg to a height of 0.90 m above the ground. 4) Sheila has just arrived at the airport and is dragging her suitcase to the luggage check-in desk. She pulls on the strap with a force of 190 N at an angle of 35e to the horizontal to displace it 45 m to the desk. Determine the work done by Sheila on the suitcase. 5) Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s. 6) If the roller coaster car in the above problem were moving with twice the speed, then what would be its new kinetic energy? 7) Missy Diwater, the former platform diver for the Ringling Brother's Circus, had a kinetic energy of 12 000 J just prior to hitting the bucket of water. If Missy's mass is 40 kg, then what is her speed? BONUS QUEESTION A 900-kg compact car moving at 60 mi/hr has approximately 320 000 Joules of kinetic energy. Estimate its new kinetic energy if it is moving at 30 mi/hr. (HINT: use the kinetic energy equation as a "guide to thinking.")

Explanation / Answer

3,

Work done by lamae

W=mgh=300*9.81*0.9

W=2648.7 Joules

4.

Work done by sheila on the suitcase is

W=FdCos(o) =190*45*Cos35

W=7003.75 Joules

5.

Kinetic energy

K=(1/2)mV2=(1/2)*625*18.32

K=104653 Joules

6.

Now V=2*18.3=36.6 m/s

K=(1/2)*625*36.62=418612

7.

Since

K=(1/2)mV2

12000= (1/2)*40*V2

V=24.5 m/s

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