b. what is the electric potential barley above the surface of the charged cell o

Question

b. what is the electric potential barley above the surface of the charged cell of radius 10 micrometers?
c. with what velocity does the sodium ion exit the cell wall so that it barley touches the charged cell in the right in the above picture? hint use conservation of energy
d. what is the electric field needed in this problem to accelerate the sodium ion to barley hit the charged cell?

cell walls are semi permeable to allow potassium ions (K') or sodium ions (Na') to enter and it the cell as necessary for cellular function. Hence, a cell wall can be modeled by a parallel plate capacitor with a dielectric constant of 9. Below is a schematic of a cell wall with the electric field lines shown within the cell wall of thickness 20 nm. In this particular cell wall, sodium ions of mass 3.82x1026 kg are accelerated through the cell wall and exit the cell traveling towards an extremely distant charged cell of radius 10 m which also has an excess charge of 10 protons. ex Cell Wall Outside of the human cell 0 Charged Cel

Explanation / Answer

part B:

electric potential V = KQ/r

V = 9e9 * 10*1.6*10^-19/(10e-6)

V = 1.44 mV

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part C:

KE = 0.5 mv^2 = eV

v^2 = 2 eV/m

v^2 = (2* 10*1.6*10^-19* 1.44 *10^-3)/(3.82*10^-26)

v = 347.31 m/s

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part D:

use v^2 = 2 a S

a = v^2/2S

a = 347.31^2/(2 * 20 *10^-9)

a = 3.01*10^12 m/s^2

so now use ma = Eq

E = ma/q

E = 3.01*10^12* 3.82*10^-26/(10*1.6 *10^-19)

E = 7.2 *10^4 N/C

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