\"A Chapter 21 Homework xe A 50.0- Resistor, A 0.10 X \\M Inbox-msteltz@emích.e

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"A Chapter 21 Homework xe A 50.0- Resistor, A 0.10 X M Inbox-msteltz@emích.e X > C Not secure | www.webassign.net/web/Student/Assignment-Responses/submit?dep. 179 16648#08 Apps NeuMoDx Molecula Other b 8. 0.3/0.52 points | Previous Answers SerCP11 21.P.022 My Notes Ask Your Tea A 45.0-2 resistor, a 0.100-H inductor, and a 10.0-uF capacitor are connected in series to a 60.0-Hz source. The rms current in the circuit is 2.90 A. Find the rms voltages across the following (a) the resistor 130.5 (b) the inductor 109.3 (c) the capacitor 769.6 (d) the RLC combination Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V (e) Sketch the phasor diagram for this circuit. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen This answer has not been graded yet.

Explanation / Answer

a) V = IR = 2.9*45 = 130.5 V

b) V = I*Xl = I*2pi*f*L

= 2.9*2pi*60*0.1

= 109.3 V

c) V = IXc = I*(1/2pi*f*C)

= 2.9*(1/2pi*60*10*10^-6)

= 769.6 V

d) R = 45 ohm

Xl = 37.69 ohm

Xc = 265.38 ohm

Z = sqrt(R^2 + (Xc-Xl)^2)

= sqrt(45^2 + (265.38 - 37.69)^2)

= 232.1 ohm

V = IZ = 2.9*232.1 = 673.07 V

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