I have an answer key, but I would like to k ow how to actually solve the problem
ID: 775807 • Letter: I
Question
I have an answer key, but I would like to k ow how to actually solve the problems.
Explanation / Answer
pOH = -log [OH-]
= -log (0.0150)
= 1.82 [answer to 13]
pH = 14 - pOH
= 14 - 1.82
= 12.18 = (12.2) [answer to 14]
15.
pOH = -log [OH-]
= -log (0.010)
= 2.0
pH = 14 - pOH
= 14 - 2
= 12 [answer]
16. pH = 4.93 = - log [H+]
[H+] = antilog ( - 4.93) = 10-4.93
= 1.17 * 10-5 M
HZ ----------> H+ + Z-
0.020 --- - I
(- 1.17 * 10-5) 1.17 * 10-5 1.17 * 10-5 C
(0.020 - 1.17 * 10-5) 1.17 * 10-5 1.17 * 10-5 E
so Ka = [ 1.17 * 10-5 ] [1.17 * 10-5 ]
(0.020 - 1.17 * 10-5)
Ka = 6.9 * 10-9
Its option D and not B
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