Determine the value of the equilibrium constant, Kgoal, for the reaction N2(g) +

Question

Determine the value of the equilibrium constant, Kgoal, for the reaction N2(g) + H2O(g) NO(g) + 1 / 2 N2H4(g), Kgoal = ? by making use the following information: N2(g) + O2(g) 2NO(g), K1 = 4.10 x 10-31 N2(g) + 2H2(g) N2H4(g), K2 = 7.40 x 10-26 2H2O(G) 2H2(g) + O2(g), K3 = 1.06 x 10-10 Express your answer numerically. Kgoal = Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g) P4(s) + 10Cl2(g), Kgoal = ? by making use of the following information: P4(s) + 6Cl2(g) 4PCl3(g), K1 = 2.00 x 1019 PCl5(g) PCl3(g) + Cl2(g), K2 = 1.13 x 10-2 Express your answer numerically. Kgoal =

Explanation / Answer

Part A

adding eq. 1 and 2 =

2N2+ O2+H2 --->> 2NO + N2H4 K3 k_1 = K1* K2

Adding above equation and eq. 3

2N2 + 2H20 -->> 2NO + N2H4 k_2 = k_1 * K3 = K1* K2* K3

Dividing above eq. by 2 gives the desired equation:

N2 + H20 -->> NO + (1/2) N2H4 Kgoal = k_2 ^(1/2)

Kgoal=(K1* K2 * K3 )^ (1/ 2) = 1.7933 * 10^-33

Part B

4* equation2 + reverse of equation1 gives us

4PCl5 ---> P4 +10 Cl2 Kgoal = (K2)^4 / (K1)= 8.1524 * (10^-28)

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