1 .Which of the following is an advantage of using squash preparations, as oppos

Question

1 .Which of the following is an advantage of using squash preparations, as opposed to sectioned material? a .Whole cells can be observed b.Squashing allows all objects in a 3D cell to be seen on the same focal plane c.Both a) and b) 2. If 3.27 g of salicylic acid is reacted with 61 mL methanol, what is the maximum mass of product (oil of wintergreen) that could be formed? The density of methanol is 0.791 g/mL. Give your answer in grams with 3 significant figures. 3.Name the esters formed in Question 2. (Don't worry about the order. Ignore Water) ____, _____, ____ ,____. 4.Match the following acids and alcohols to their corresponding esters. A. CH3COO(CH2)3CH3 + H2O B. CH3COOC6H5 + H2O. C. CH3CH2COOC6H5 + H2O CH3COOH + CH3(CH2)2CH2OH ---> D. CH3CH2COO(CH2)3CH3 + H2O CH3COOH + C6H5OH ---> CH3CH2COOH + CH3(CH2)2CH2OH ---> CH3CH2COOH + C6H5OH --->

Explanation / Answer

salicylic acid + methanol ---> methylsalicylate (Acid is used as a catalyst.) =========================================================================== mass salicylic acid = 3.27 g ================================================================= mass methanol = 61.0 mL(0.791 g)/(1 mL) = 48.25 g =========================================================================================== molar mass of salicylic acid(C7H6O3) = 138.12 g/mol ====================================================================== molar mass of methanol = 32.04 g/mol =============================================================================== molar mass methylsalicylate(C8H8O3) = 152.1494 g/mol ============================================================================================= each mole of salicylic acid present you obtain 1 mole of methylsalicylate. ================================================================================= moles salicylic acid(SA) = 3.27 g(1 mole)/(138.12 g) =0.0236 mole ============================================================================================ moles methanol = 48.25 g(1 mole)/(32.04 g) = 1.5059 mole =================================================================================== = max. mass of methylsalicylate(MS) = 0.0236 mole SA[(1 mole MS)/(1 mole SA)][(152.15 g)/(1 mol) = 1.5 g MS ========================================================================================= CH3(CH2)3OH + CH3CO2H = CH3COO(CH2)3CH3 + H2O =========================================================================================== C6H5OH + CH3COOH = CH3COOC6H5 + H2O ======================================================== 12 CH3COOH + 3 CH3(CH2)2CH2OH = 4 CH3CH2COOC6H5 + 19 H2O =============================================================== 6 CH3COOH + CH3(CH2)2CH2OH = 2 CH3COOC6H5 + 9 H2O ==================================================================================CH3COOH + CH3(CH2)2CH2OH = CH3COO(CH2)3CH3 + H2O ===============================================================================

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