the specific gravity of gasoline is approximately 0.70 (a) determine the mass (k

Question

the specific gravity of gasoline is approximately 0.70 (a) determine the mass (kg) of 50.0 liters ofgasoline. (b) the mass flow rate of gasoline exiting a refinery tank is1150 kg/min. Estimate the volumetric flow rate in litera/s. (c) Estimate the average mass flow rate (Lbm/min) delivered bygasoline pump. (d) Gasoline and kerosene (spacific gravity = 0.82) areblended to obtain a mixture with a spacific gravity of 0.78.Calculate the volumetric ratio (volume of gasoline.volume ofkerosene) of the two compounds in the mixture, assumingVblended =Vgasoline + Vkerosene. (a) determine the mass (kg) of 50.0 liters ofgasoline. (b) the mass flow rate of gasoline exiting a refinery tank is1150 kg/min. Estimate the volumetric flow rate in litera/s. (c) Estimate the average mass flow rate (Lbm/min) delivered bygasoline pump. (d) Gasoline and kerosene (spacific gravity = 0.82) areblended to obtain a mixture with a spacific gravity of 0.78.Calculate the volumetric ratio (volume of gasoline.volume ofkerosene) of the two compounds in the mixture, assumingVblended =Vgasoline + Vkerosene.

Explanation / Answer

0.70 specific gravity => density of 0.70 g/mL a) 50 L *(1000 mL/L)*(0.70 g/mL) *(1 kg/1000g) = 35 kg b) 1150 kg/min *(1000 g/ 1kg )*(1 mL/0.70 g) *(1 L/1000 mL) *(1min/60s) = 27.38 L/s ~ 27 L/s c) 1150 kg/min *(1lb/ 0.45359237 kg) = 2532 lb/min 1 pound =0.45359237 kilograms d) Vblended*0.78 = Vgasoline*0.70 + Vkerosene*0.82 Vblended = Vgasoline + Vkerosene 0.78*(Vgasoline + Vkerosene) = Vgasoline*0.70 + Vkerosene*0.82 0.08 *Vgasoline = 0.04*Vkerosene Vgasoline/Vkerosene = 0.04/0.08 = 0.5

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