What are the concentration of each of the ionsin a saturated solution of PbBr2 g

Question

What are the concentration of each of the ionsin a saturated solution of PbBr2 given that the Ksp of PbBr2 is2.1X 10^-6? if 5 g of PbBr2 are dissolved in water to make 1L ofsolution and this is then brought to 25 C, would the solution besaturated, unsaturated, or supersaturated???

PLZ HELP, thank you
WILL RATE LIFE SAVER What are the concentration of each of the ionsin a saturated solution of PbBr2 given that the Ksp of PbBr2 is2.1X 10^-6? if 5 g of PbBr2 are dissolved in water to make 1L ofsolution and this is then brought to 25 C, would the solution besaturated, unsaturated, or supersaturated???

PLZ HELP, thank you
WILL RATE LIFE SAVER

Explanation / Answer

PbBr2 => Pb2+   + 2Br- Q = [Pb2+][Br-]2 5 g PbBr2*(1mol/367 g) = 0.0136239782 moles That is dissolved in 1 L, so 0.013624 moles dissolved 1 mole of Pb2+ from each mole of salt dissolved, so [Pb2+] =0.013624 Since 2 moles of Br- are formed for each mole of saltdissolved, [Br-] = 2*0.013624 = 0.0272479564 M Q = (0.013624)*(0.0272479564)2 = 1.0115138e-5 Q > Ksp, so the solution is supersaturated (too many ions aredissolved); if a seed crystal were introduced into the solution, aprecipitate would form.

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