The Occupational Safety and Health Administration has set the limit on the maxim

Question

The Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worker can breathe at 0.500% by mole. If dry ice (solid CO2) is sublimating (becoming a gas) in a room at a rate of 0.680 mol/min, what is the minimum rate that fresh air has to be supplied to the room so that the concentration of CO2 in the room doesn't exceed 0.500% by mole? Assume the room is well mixed, and the volume of the solid dry ice does not change. What is the percent by mass of oxygen in a gaseous mixture whose molar composition is 0.500% CO2 and 99.500% air? The composition of air is 21% mole O2, 79% mole N2, and has an average molar mass of 29.0 g/mol.

Explanation / Answer

1), 0.680 mol/min/ 0.500% - 0.680mol=135.32 mol/min.

2), Assume 100mole total.

m(CO2)=0.5mol*44g/mol=0.22 g

m(O2)=99.5*0.21*32g/mol=668.64g

m(N2)=99.5*0.79*29g/mol=2279.545g

==>O2%=668.64/(0.22+668.64+2279.545)=22.68

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