An experiment was performed in which an empty 100-mL graduatedcylinder was weigh

Question

An experiment was performed in which an empty 100-mL graduatedcylinder was weighed. It was weighed once again after it had beenfilled to the 10.0-mL mark with dry sand. A 10-mL pipet was used totransfer 10.00-mL of methanol to the cylinder. The sand-methanolmixture was stirred until bubbles no longer emerged from themixture and the sand looked uniformly wet. The cylinder was thenweighed again. Use the data obtained from this experiment(anddisplayed at the end of this problem) to find the density of thedry sand, the density of methanol, and the density of sandparticles. Does the bubbling that occurs when the methanol is addedto the dry sand indicate that the sand and methanol arereacting? Mass of cylinder plus wetsand        45.2613 g Mass of cylinder plus drysand         37.3488g Mass of emptycylinder                    22.8317g Volume of drysand                         10.0mL Volume of sand +methanol              17.6mL Volume ofmethanol                        10.00mL An experiment was performed in which an empty 100-mL graduatedcylinder was weighed. It was weighed once again after it had beenfilled to the 10.0-mL mark with dry sand. A 10-mL pipet was used totransfer 10.00-mL of methanol to the cylinder. The sand-methanolmixture was stirred until bubbles no longer emerged from themixture and the sand looked uniformly wet. The cylinder was thenweighed again. Use the data obtained from this experiment(anddisplayed at the end of this problem) to find the density of thedry sand, the density of methanol, and the density of sandparticles. Does the bubbling that occurs when the methanol is addedto the dry sand indicate that the sand and methanol arereacting? Mass of cylinder plus wetsand        45.2613 g Mass of cylinder plus drysand         37.3488g Mass of emptycylinder                    22.8317g Volume of drysand                         10.0mL Volume of sand +methanol              17.6mL Volume ofmethanol                        10.00mL

Explanation / Answer

Given Mass of cylinder plus wet sand,m = 45.2613 g          Mass ofcylinder plus dry sand , m' = 37.3488 g          Mass of emptycylinder , m"= 22.8317 g         Volume of drysand , V'= 10.0 mL         Volume ofsand + methanol ,V = 17.6 mL         Volume ofmethanol, V" =10.00mL Mass of dry sand = Mass of cylinder plus drysand - Mass of empty cylinder                             =m' - m''                            = 14.5171 g Volume of dry sand , V'' = 10.0 mL Density of the dry sand = Mass of dry sand / Volumeof dry sand                                   = 14.5171 /10                                   = 1.45171 g / mL Mass of methanol = Mass of cylinder plus wet sand - Mass ofcylinder plus dry sand                            = m - m'                            = 45.2613 - 37.3488                            = 7.9125 g Volume of methnol = 10.0 mL Density of methanol = mass of methanol / Volume ofmethanol                                      =7.9125 / 10                                     = 0.79125 g / mL

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