calculate the molality and mass percient of a queous solution of Na2CO3 which ha

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solute mole fraction = (number of moles of solute)/(number of moles of solute+solvent) => (number of moles of water)/(number of moles of Na2CO3) = (1/0.365)-1 = 1.7397 (mass of water/18)/(mass of Na2CO3/106) = 1.7397 => mass of water/mass of Na2CO3 = 0.2954 => mass percent of Na2CO3 = [0.2954/(1+0.2954)]*100 = 22.8 % Now, mass of water/mass of Na2CO3 = 0.2954 => mass of Na2CO3/mass of water = 1/0.2954 = 3.3852 => molality = moles of Na2CO3/mass of water = 3.3852/106 => molality = 0.032

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