H2 (g) + 1/2 O2 (g)----H2O (l); triangleH= -285.8kJ I don\'t know how to arrive
ID: 76560 • Letter: H
Question
H2 (g) + 1/2 O2 (g)----H2O (l); triangleH= -285.8kJI don't know how to arrive at this. Please help H2 (g) + 1/2 O2 (g)----H2O (l); triangleH= -285.8kJ
I don't know how to arrive at this. Please help
Explanation / Answer
The direction of heat flow for a balanced equation is written tothe right of the chemical equation as a "delta H". H2 (g) + 1/2 O2 (g) --> H2O (l); Delta H = -285.8 kJ A negative delta H means heat is a product. A positive delta Hmeans heat is required (as a reactant). H is the symbol forEnthalpy. Delta H means the change in enthalpy for thereaction. For some less that professional methods, Using the "delta triangle"or the word "heat" can be used on the appropriate side of theequation. There are also specialized form that can be used. The heat ofcombustion is more precisely termed the enthalpy of combustion andis given the symbol Hcomb. For example: 2HgO to 2Hg and Oxygen 2HgO ---------> 2Hg + Oxygen To represent that heat is applied, just place a triangle above thebody of the arrow. Hope this helps- Please Rate!
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