Show that the reaction of ammonia with mercury(I) chloride is an oxidation-reduc

Question

Show that the reaction of ammonia with mercury(I) chloride is an oxidation-reduction reaction. (Include a reaction equation. Since this is a redox reaction, CLEARLY indicated in your answer what is being oxidized and what is being reduced along with changes in oxidation states.)

Explanation / Answer

Hg2Cl2 (s) + 2NH3 (aq) ------> Hg (s) + HgNH2Cl2 (s) + NH4Cl (aq) redox is REDuction OXidation and reduction = "reduction in charge" and oxidation = the opposite of reduction.. "increase in charge" *************** Ag in AgCl is +1 Cl in AgCl is -1 N in NH3 is +3 H in NH3 is -1 Ag in Ag(NH3)2(1+) is +1.. why? NH3 is a metal ligand with zero charge Cl in Cl- is -1 no charge changes so no redox... >>> notice the charge on Ag(NH3)2(1+) is +1? you left that off **************** Ag in Ag(NH3)2(+1) is +1 N in Ag(NH3)2(+1) is -3 H in Ag(NH3)2(+1) is +1 Cl in Cl- is -1 H in HNO3 is +1 N in HNO3 is +5 O in HNO3 is -2 Ag in AgCl is +1 Cl in AgCl is -1 1st N in NH4NO3 is -3... NO3 is -1.. right? each H is +1.. so N in NH4 is -3 H in NH4NO3 is +1 2nd N in NH4NO3 is +5... NO3 is -1.. O is -2.. so N must be +5.. +5-3x(-2) = -1 O in NH4NO3 is -2 again.. not redox.. no charge changes... ************ Hg in Hg2Cl2 is +1 Cl in Hg2Cl2 is -1 N in NH3 is -3 H in NH3 is +1 Hg in Hg(s) is 0 Hg in HgNH2Cl is +2.. why? NH2 is -1.. Cl is -1 N in HgNH2Cl is -3.. NH2 is -1 H in HgNH2Cl is +1 Cl in HgNH2Cl is -1 N in NH4Cl is -3 H in NH4Cl is +1 Cl in NH4Cl is -1 so.. 1 Hg goes from +1 to 0 and is "reduced" by gaining an electron 1 Hg goes from +1 to +2 and is "oxidized" by losing an electron.. (to the other Hg) so this IS a redox reaction..

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