Suppose you have 20.81 g of water,initially at 25.00 o C, in a perfectly insulat

Question

Suppose you have 20.81 g of water,initially at 25.00 oC, in a perfectly insulatedcontainer. You then add water which is at 83.71 oC tothe container until the combined sample of water has a temperatureof 58.71 oC. What mass (in grams) of hot water wasadded? Do not include units (g) in your answer. The specific heatcapacity of water is 4.184 J g-1oC-1. Suppose you have 20.81 g of water,initially at 25.00 oC, in a perfectly insulatedcontainer. You then add water which is at 83.71 oC tothe container until the combined sample of water has a temperatureof 58.71 oC. What mass (in grams) of hot water wasadded? Do not include units (g) in your answer. The specific heatcapacity of water is 4.184 J g-1oC-1.

Explanation / Answer

Qcool = Qheat = M*Cp*(delT) unknown mass *4.18 J/g/C *(83.71 - 58.71)C = 20.81 g * 4.18J/g/C *(58.71 -25)C unknown mass = 20.81*(58.71-25)/(83.71-58.71) = 28.06 grams

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