How much energy is released in the decay of 250 mg of 239 Pu? 239 Pu+ 4 He -> 23

Question

How much energy is released in the decay of 250 mg of239Pu?

239Pu+ 4He     ->     235U   

239Pu= 239.006 g/mol….4He =4.0015g/mol…235234.9934 g/mol

I know until converting the mg to grams which is .25 grams thenI get lost.

Explanation / Answer

I think you mean Pu-239 -> U-235 +He-4        ( alpha particlesare a product) m = (234.9934 +4.0015)-(239.0066) = -0.0017 g/mol E = m*c2 = (0.0017g/mol) *(1 kg/1000g) *(3e8m/s)2 = 1.53x 1011 J/mol                     Note kg*m2/s2 = J 0.25 g Pu *(1 mol/ 239.006 ) *(1.53e11 J/mol) = 1.60 e 8Joules Edited for errors. Below post is correct

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