consider the titration of 100. ml of 0.125 M Fe 2+ by 0.0500 M MnO 4 - in 1M H 2

Question

consider the titration of 100. ml of 0.125 M Fe2+by 0.0500 M MnO4- in 1M H2SO4,using Pt and saturated calomel electrodes to find the endpoint. a) write down the balanced titration reaction. b) write the analyte half reaction for the indicatorelectrode consider the titration of 100. ml of 0.125 M Fe2+by 0.0500 M MnO4- in 1M H2SO4,using Pt and saturated calomel electrodes to find the endpoint. a) write down the balanced titration reaction. b) write the analyte half reaction for the indicatorelectrode

Explanation / Answer

The Balenced Chemical Reaction is 5 Fe2+ + MnO4-+8H+ ------> 5Fe+3 + Mn2+ +4H2O   M1 = Molarity of Fe2+ = 0.125 M V1 = Volume of Fe2+ =100 mL n1   = Numer of moles ofFe2+ =5    M2= Molarityof  MnO4- = 0.0500M V2 = Volume of MnO4- = ?    n2 = Numer of molesof MnO4-   = 1        M1V1 / n1   =M2V2/n2     V2 =M1V1/ n1   *n2/M2          = 0.125M*100mL/5 *1/0.0500 M           = 50mL    At End Point 50 mL of MnO4- is consumed . The H2SO4 is used inthis reaction beause of In AcidicMedium   Fe2+ is not convertedinto   Fe+3 before going to reaction . A ) The Balenced Titration reaction is          [Fe2+ --------> Fe+3 + e- ] *5            MnO4- + 4H +  +5e- ------> Mn+2+4 H2O        ___________________________________________           5Fe2+ + MnO4- +8H+------> 5Fe+3 + Mn2+ +4H2O B) Here The Analyte Indicatore Electrode Pt        Pt-----> Pt+2 + 2 e-          = 0.125M*100mL/5 *1/0.0500 M           = 50mL    At End Point 50 mL of MnO4- is consumed . The H2SO4 is used inthis reaction beause of In AcidicMedium   Fe2+ is not convertedinto   Fe+3 before going to reaction . A ) The Balenced Titration reaction is          [Fe2+ --------> Fe+3 + e- ] *5            MnO4- + 4H +  +5e- ------> Mn+2+4 H2O        ___________________________________________           5Fe2+ + MnO4- +8H+------> 5Fe+3 + Mn2+ +4H2O B) Here The Analyte Indicatore Electrode Pt        Pt-----> Pt+2 + 2 e-        ___________________________________________           5Fe2+ + MnO4- +8H+------> 5Fe+3 + Mn2+ +4H2O B) Here The Analyte Indicatore Electrode Pt        Pt-----> Pt+2 + 2 e-

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