If each molecule of acetanilide produces onemolecule of hydrogen bromide, what v
ID: 75959 • Letter: I
Question
If each molecule of acetanilide produces onemolecule of hydrogen bromide, what volume of HBr gas should beevolved from the reaction? mass of acetanilide used: 25mg=.025g molar mass=135.17g/mol moles=.025g/135.17g=1.84*104mol of HBr I am not sure how to go about finding the volume of HBr gasevolved..... mass of acetanilide used: 25mg=.025g molar mass=135.17g/mol moles=.025g/135.17g=1.84*104mol of HBr I am not sure how to go about finding the volume of HBr gasevolved..... If each molecule of acetanilide produces onemolecule of hydrogen bromide, what volume of HBr gas should beevolved from the reaction?Explanation / Answer
Number ofmoles of acetanilide taken = 0.025 g / 135.17g/mol = 1.84 x 10-4 mol Number of moles of HBr formed = 1.84 x10-4 mol Number of moles = mass / molar mass Mass of HBr formed = 1.84 x10-4 molees * 80.91 g/mol = 0.0149 g Density of HBr gas = 3.307 g /L Density = mass / volume Volume of HBr gas = 0.0149 g / 3.307 g/L = 0.0045 L Number ofmoles of acetanilide taken = 0.025 g / 135.17g/mol = 1.84 x 10-4 mol Number of moles of HBr formed = 1.84 x10-4 mol Number of moles = mass / molar mass Mass of HBr formed = 1.84 x10-4 molees * 80.91 g/mol = 0.0149 g Density of HBr gas = 3.307 g /L Density = mass / volume Volume of HBr gas = 0.0149 g / 3.307 g/L = 0.0045 LRelated Questions
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