The endpoint in the titration is \"overshot\" A. is the reported molar concentra

Question

The endpoint in the titration is "overshot" A. is the reported molar concentration of the hydrochloric acid solution too high or too low. B. As a result of this poor titration technique, is the reported number of moles of B4O5(OH)4^2 would be too high or too low?

Explanation / Answer

1) A 10 mL sample of HCl solution was transferred by pipet to an Erlenmeyer flask and then diluted by adding about 40 mL of distelled water. What is the approximate H3O+ concentration and pH of the solution in the flask before the titration begins? (approx concentration of HCl is 0.5 M) 2) Phenolphthalein indicator was added, and the solution in the flask was titrated with 0.215 M NaOH until the indicator turned pink (pH = 8-9). The exact volume of NaOH required was 22.75 mL. Use the following equation to calculate the concentration of HCl in the original 10 mL sample ==> Mb x Vb = nMa x Va Mb = molarity of standadrd base solution Vb = volume of base added n = mole ratio Ma = unknown molarity of acid solution Va = initial volume of acid solution 3) One student accidentally "overshot" the endpoint and added 23.90 mL of 0.215 M NaOH. Is the calculated concentration of HCl likely to be too high or too low as a result of this error? Why? I think that you have a lot to catch up --- please work hard (on chem). 1) this sample got diluted 5 times, thus the approximate new concentration of HCl or H3O+ is 0.1 M (since HCl ionize to H3O+ and Cl-), and pH ˜ 1 2) 22.75 mL of 0.215 M NaOH is 0.02275*0.215 = 0.004891 Mol of NaOH, which may completely neutralize 0.004891 Mol of HCl. So the original molar concentration in 10ml HCl is: 0.004891/0.01 = 0.489M. 3) The relative error is (23.90 - 22.75)/22.75 = 1.15/22.75 = 5.05% The calculated concentration of HCl likely to be 5.05% high, since the concentration calculation of HCl is based on molar mass of NaOH used.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.