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The reaction between ethyl iodide and hydroxide ion in ethanol(C2H5OH) solution

ID: 75545 • Letter: T

Question

The reaction between ethyl iodide and hydroxide ion in ethanol(C2H5OH) solution C2H5I+OH=C2H5OH+I has an activation energy of 86.8KJ/mol and a frequency factorof 2.10*10^11 M^(-1)S^(-1) Q: Equal volumes of a 0.0239 M KOH in ethanol solution and a0.0373 M C2H5I in ethanol solution are mixed. Assuming the reactionis first order in each reactant, what is the initial rate ofreaction at 35 degree celsius? Hint: Do your dilutions first! thank you so much! life saver rewarded if answer's satisfactory! The reaction between ethyl iodide and hydroxide ion in ethanol(C2H5OH) solution C2H5I+OH=C2H5OH+I has an activation energy of 86.8KJ/mol and a frequency factorof 2.10*10^11 M^(-1)S^(-1) Q: Equal volumes of a 0.0239 M KOH in ethanol solution and a0.0373 M C2H5I in ethanol solution are mixed. Assuming the reactionis first order in each reactant, what is the initial rate ofreaction at 35 degree celsius? Hint: Do your dilutions first! thank you so much! life saver rewarded if answer's satisfactory!

Explanation / Answer

Formula:                       k  = A e-Ea / RT Where k is the rate constant            Ais the frequency factor           Ea is the activation energy           R isthe gas constant ( 8.3145 J / mol.K)           T isthe kelvin temperature It is also mentioned that the reaction is first order ineach reactant   Then Initial rate = k[OH-][C2H5I] Data:             [C2H5I]= 0.0373 M            [OH-]    = 0.0239 M                  A    = 2.10*10^11 M^(-1)S^(-1)                  Ea  = 86.8KJ/mol                   T   = 35 + 273 K                         =308 K From this data k value can be found at 350C.               k   = 2.10*10^11 M^(-1)S^(-1) e-86.8 * 1000 J/mol / 8.3145 J / mol.K * 308 K                        =2.10*10^11 M^(-1)S^(-1) * 1.90 * 10-15                       = 3.99 * 10-4 M /s Now the k value is substituted in the expression,     Initial rate =  3.99 *10-4 M /s  ( 0.0373)( 0.0239 )                         =3.56 * 10-7          
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