H = -345.3kcal/mol S = 32cal/molK Temperature = 46 0 C A + B <-- --> AB a. Indic

Question

H = -345.3kcal/mol                                                      S = 32cal/molK Temperature = 460 C                                          A + B <-- --> AB a.   Indicate if the equation is exothermic orendothermic- rewrite the equation. b. Using the free energy formula, would this equation bespontaneous or non spontaneous? H = -345.3kcal/mol                                                      S = 32cal/molK Temperature = 460 C                                          A + B <-- --> AB a.   Indicate if the equation is exothermic orendothermic- rewrite the equation. b. Using the free energy formula, would this equation bespontaneous or non spontaneous?

Explanation / Answer

Given H = -345.3 kcal / mol                   = -345300 cal / mol temperature T = 46 oC = 46 + 273                       = 319 K which is negative ,This indicates the reaction isexothermic we know that G = H + T S                            = ( -345300 ) + ( 319 * 32 cal / mol K )                            = -335092 cal / mol                            = -335.092 cal / mol G is negative So,it is spontaneous

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