Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

without doing any calculations determine what the sign of delta s will be for th

ID: 751039 • Letter: W

Question

without doing any calculations determine what the sign of delta s will be for the following equation 2CO(g)+O2(g)>>>2CO2 (g) that's all we were given and i'm not sure how to solve without any additional information.

Explanation / Answer

the idea is that you have to arrange the bottom 3 equations so that they sum up to the desired equation. You may have to flip them around (in which case the sign of dH changes) and you may have to multiply them by a constant... you want C(s) + H2O(g) ---> CO(g) + H2(g) and you have. (1).. C(s) + O2(g) ---> CO2(g)... ... ....?H = -393.5 kJ (2).. 2 CO(g) + O2(g) ---> 2 CO2(g)... ?H = -566.0 kJ (3).. 2 H2(g) + O2(g) ---> 2 H2O(g)... .?H= -483.6 kJ now if you notice you want C(s) on the left. only equation 1 has C(s) on the left. and you want 1 C(s) and equation (1) has 1 C(s).. so we don't have to flip that around and we don't have to multiple by a constant. (1).. C(s) + O2(g) ---> CO2(g)... ... ....?H = -393.5 kJ now you know that you need CO(g) on the right. the second equation has it on the left. And you need 1 and it has 2. So we need to multiple it by 1/2 and flip the equation around. now we have this. (1).. C(s) + O2(g) ---> CO2(g)... ... ..... ..?H = -393.5 kJ (2).. 1 CO2(g) ---> 1 CO(g) + ½ O2(g)... ?H = +283.0 kJ now we need H2O(g) on the left.. equation (3) has it on the right. and we need 1 and it has 2.. so again.. we flip it around and divide by 2 (1).. C(s) + O2(g) ---> CO2(g)... ... ..... ..?H = -393.5 kJ (2).. 1 CO2(g) ---> 1 CO(g) + ½ O2(g)... ?H = +283.0 kJ (3).. 1 H2O(g) ---> 1 H2(g) + ½ O2(g)... .?H= +241.8 kJ NOTE... make sure to flip the signs of ?H AND multiply it or divide it according ! ************** now.. if we sum those up we get.. (1).. C(s) + O2(g) ---> CO2(g)... ... ..... ..?H = -393.5 kJ (2).. 1 CO2(g) ---> 1 CO(g) + ½ O2(g)... ?H = +283.0 kJ (3).. 1 H2O(g) ---> 1 H2(g) + ½ O2(g)... .?H= +241.8 kJ ____ ____ _____ _______ _____ _____ _____ ____ ____ SUM. .C(s) + H2O(g) ---> CO(g) + H2(g)... ?H= +131.3 kJ