What is the molecular equation, total ionic equation, and net ionic equation for

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The general steps you need to take are as follows: 1. Write the molecular equation for the reaction. 2. Balance the molecular equation for the reaction. 3. Rewrite the equation showing all substances in their ionic form while in solution. This is the ionic equation. 4. Identify and cancel all the spectator (soluble) ions on both sides of the equation. This will yield the net-ionic equation. As an example, to find the net ionic for your first equation: Steps 1&2: Write and Balance the molecular equation (already done in this case) Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3 Step 3: Rewrite the equation showing all substances in their ionic form while in solution. This is the ionic equation. According to the solubility rules, everything in the equation is soluble with the exception of Cu(OH)2, so everything else will dissolve and your ionic equation should look like this (sorry, looks a little sloppy, but the charges should be superscripts, and the "aq" and "s" shold be subscripts): Cu 2+(aq) + 2NO3-(aq) + 2Na+ (aq) + 2OH-(aq) -> Cu(OH)2 (s) + 2Na+ (aq) +2NO3 -(aq) Step 4: Cancel the spectator (aq) ions, and you whatever is left is the net ionic equation, so your final answer should be: Cu 2+ (aq) + 2OH- (aq) -> Cu(OH)2 (s) Check the site listed below for additional examples and solubility rules. You might need a list of common ions also. Hope this helps!

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