The gaseous reaction H2 + Cl2 <--> 2HCl is a equilibriumwith 10.0 moles of Cl2 i

Question

The gaseous reaction H2 + Cl2 <--> 2HCl is a equilibriumwith 10.0 moles of Cl2 in the the reaction chamber. For each of thefollowing changes, when the reaction returns to equilibrium, willthere be more. less, or the same amount of Cl2? a. A small amount of H2 is added. b. A small amount of HCl is added. c. Some NaO(s) is added, which reacts with the HCl to formsolid NaCl and H2O vapor. d. A catalyst is added. e. The reaction is exothermic. The temperature is decreased atiny amount. f. A small amount of Cl2 is added. The gaseous reaction H2 + Cl2 <--> 2HCl is a equilibriumwith 10.0 moles of Cl2 in the the reaction chamber. For each of thefollowing changes, when the reaction returns to equilibrium, willthere be more. less, or the same amount of Cl2? a. A small amount of H2 is added. b. A small amount of HCl is added. c. Some NaO(s) is added, which reacts with the HCl to formsolid NaCl and H2O vapor. d. A catalyst is added. e. The reaction is exothermic. The temperature is decreased atiny amount. f. A small amount of Cl2 is added.

Explanation / Answer

a) Less Cl2 because you've shifted equilibrium to theright according to LeChatelier's principle. b) More because equil. is shifted to the left c) you're using up the HCl so there will be less Cl2 asmore of it reacts with the H2 to make more HCl torestore equilibrium d)No change e)If rxn is exothermic, heat is released--heat is a product. Youdecrease the heat, and equilibrium will shift to the right, so theCl2 will decrease f)haha what? If you add more Cl2, then you have more ofit, but equilibrium will be restored and there should be the sameamount of Cl2 If you want more details, PM or ask. :)

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