In acidic solution Given the partial equation ?MnO4 +?SO3 2- yields? Mn2+ ?SO4 2

Question

In acidic solution Given the partial equation ?MnO4 +?SO3 2- yields? Mn2+ ?SO4 2- what must the coefficients be so that the electrons are balanced?

Explanation / Answer

MnO4- + SO3 2- + H+ ---> Mn2+ + SO4 2- + H20 Mn is reduced, from 7+ to 2+, gaining 5 electrons S is oxidized, from 4+ to 6+, losing 2 electrons so we give coefficients of 5 and 2 to S and Mn 2 MnO4- + 5 SO3 2- + 6 H+ ----> 2 Mn2+ + 5 SO4 2- + 3 H2O This reaction must (though not stated above) take place in an acidic solution so we add H+ on the left and H2O on the right to balance first the oxygen, then the hydrogen. As a final check, charge balances, the left having 6- and the right 6- as well

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