How can the molarity of chloride ion be calculated when 16 mL (2 mL intervals) o

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2HCl + Co(NO3)2 = CoCl2 + 2HNO3 Moles of HCl: 16 mL x 1 L/1,000 mL x 12 moles/1 L = 0.192 moles Moles of Co(NO3)2: 5 mL x 1 L/1,000 mL x 0.4 moles/1 L = 0.002 moles Ratio of HCl:CoCl2 is 2:1 --> moles of CoCl2 is 0.096 Ratio of Co(NO3)2:CoCl2 is 1:1 --> moles of CoCl2 is 0.002 Thefore, Co(NO3)2 is the LR and we use 0.002 moles in calculating the molarity of Cl-ions. For every 2 HCl, there are 2 Cl-, so the moles of Cl- in HCl is 0.192 For every 1 CoCl2, there are 1 Cl-, so the moles of Cl- in CoCl2 is 0.002 Molarity = moles of solute/L of solution = 0.192 + 0.002 (moles) / 0.016 + 0.005 (L) = 9.3 M (moles/L) Hope this helps! :-)

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