a piece of aluminum metal is allowed to react with an excess quantity of nitric

Question

a piece of aluminum metal is allowed to react with an excess quantity of nitric acid and the hydrogen gas produces is collected in a gas buret by displacement of water. the other product is aluminum nitrate solution. a) write a balanced equation for this reaction. b) neglecting the effect of the vapor pressure of water on the system, calculate how many mg of aluminum would generate 85.0 mL of the gas at a temperature of 25.0 deg C and a pressure of 1.00 atm

Explanation / Answer

a.)2Al + 6HNO3 ----> 2Al(NO3)3 + 3H2 b.)PV=nRT n=PV/RT=1(0.085)/0.0821*298=3.474 x 10^-3 moles So no of moles of Al=2*n/3=2.316 x 10^-3 moles So mass=2.316 x 10^-3*27=0.0625 grams

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