Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (tab

Question

Aspartame is an artificial sweetener that is 160 times sweeter than sucrose (table sugar) when dissolved in water. It is marketed as Nutra-Sweet. The molecular formula of aspartame is C14H18N2O5. (a) Calculate the molar mass of aspartame. (Answer to the nearest 0.1 g/mol.) ? g/mol b) How many moles of molecules are present in 29.3 g of aspartame?
? mol
(c) What is the mass in grams of 6.51 mol of aspartame?
? g (d) How many molecules are in 5.6 mg of aspartame?
? molecules (e) How many atoms of nitrogen are in 2.4 g of aspartame?
? atoms (f) What is the mass in grams of 3.0 * 109 molecules of aspartame?
? g (g) What is the mass in grams of one molecule of aspartame?
? g Please answer the question marks and show your work and I may reward points. (a) Calculate the molar mass of aspartame. (Answer to the nearest 0.1 g/mol.) ? g/mol b) How many moles of molecules are present in 29.3 g of aspartame?
? mol
(c) What is the mass in grams of 6.51 mol of aspartame?
? g (d) How many molecules are in 5.6 mg of aspartame?
? molecules (e) How many atoms of nitrogen are in 2.4 g of aspartame?
? atoms (f) What is the mass in grams of 3.0 * 109 molecules of aspartame?
? g (g) What is the mass in grams of one molecule of aspartame?
? g Please answer the question marks and show your work and I may reward points.

Explanation / Answer

a) molar mass of aspartame = 294.3 g/mol (by simply adding molar masses of each constituent atom). b) no. of moles = (29.3/294.3) = 0.09956 moles no. of molecules = (no. of moles)*(Avogadro's number) = 5.99*10^22 c) mass of 6.51 mol = (6.51*294.3) = 1915.893 g d) no.of moles in 5.6 mg = (0.0056/294.3) = 1.903*10^-5 no. of molecules = (no. of moles)*(Avogadro's number) = 1.146*10^19 e) no. of moles of aspartame in 2.4 g = (2.4/294.3) = 8.155*10^-3 1 mole of aspartame has 2 mole of nitrogen atoms so 8.155x10^-3 moles of aspartame will have 2*8.155*10^-3 = 0.01631 mole no. of nitrogen atoms = 0.01631*Avogadro's number = 9.822*10^21 f) no. of moles of aspartame = (3*10^9)/Avogadro's number = 4.982*10^-15 so mass = (4.982*10^-15)*294.3 = 1.466*10^-12 g g) mass of 1 molecule = (294.3/Avogadro's number) = 4.887*10^-22 g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.