An unidentified compound (A) was reacted with bleach using the same experimental

Question

An unidentified compound (A) was reacted with bleach using the same experimental protocol as that performed in the lab. Molecule B was formed. Answering the questions below should allow you to interpret the following information in order to determine the structures of A and B. The complete combustion of 2. 0000 g of B yield 5. 1085 g CO2 and 2. 0917 g H2O. B does not have a titratable proton. Question #1: Use the combustion data to determine the empirical formula of B. Show all necessary calculations, including: #moles of the combustion products CO2 and H2O, and from that, the mass and #moles of each atom (H, C, O) which must have been in the product molecule, B.

Explanation / Answer

2.000g of B combusted yields 5.1085 g CO2 and 2.0917 g of H2O

5.1085 g CO2 / 44.01 g/mole * 1 mole C/mole CO2 = 0.11607 moles C
0.11607 moles C * 12.01 g/mole = 1.3941g C
2.0917 g H2O /18.02g/mole * 2 mole H/mole H2O = 0.23215 moles H
0.23215 moles H * 1.008 g/mole = 0.23401 g H
2g - 1.3941 - 0.23401 = 0.37189 g of O / 15.9994 g/mole = 0.023244 moles of O

Those are the quantities of each substance in the 2 gram sample.

Divide each number of moles by the smallest number of moles (oxygen)
5 moles C, 10 moles H, 1 mole O
C5H10O

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.