For the following... 23.99 g/ 10 ml KCL 39.88 g/ 10 ml KCL 56.33 g/ 10 ml KCL 75

Question

For the following...

23.99 g/ 10 ml KCL
39.88 g/ 10 ml KCL
56.33 g/ 10 ml KCL
75.02 g/ 10 ml KCL
Convert your grams/10 mL values to grams/100 mL values and plot a solubility curve for potassium chlorate. The horizontal axis is the temperature scale from 20 to 100C using 10-degree intervals, and the vertical scale is the solubility in g/100 mL.Draw a small circle around each dot, and construct a smooth curve for the observed data. Extrapolate this curve to the temperature limits of your graph by using a dashed line to indicate extrapolation.

Explanation / Answer

I am giving the conversions, It can be plotted easily thereafter 23.99 g/10 ml is equivalent to 239.9 g/100 ml 39.88 g/10 ml is equivalent to 398.8 g/100 ml 56.33 g/10ml is equivalent to 563.3 g/100 ml 75.02 g/10ml is equivalent to 750.2 g/100ml

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