How many grams are in 3 moles of substance containing strontium and chloride? So

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Explanation / Answer

Lead (II) means the lead has an oxidation state of two, therefore the charge on the Lead cation is 2+ Pb2+ nitrate always has a charge of -1 (you need to memorise this one) NO3(-) So the formula for Lead (II) nitrate is Pb(NO3)2 potassium iodide potassium is in group 1, all group 1 elements lose 1 electron to form cations with a charge of 1+ K+ iodine is in group 7, all group 7 elements gain 1 electron to form anions with a charge of 1- I- So formula for potassium iodide KI molecular equation Pb(NO3)2(aq) + 2KI(aq) ----> PbI2(s) + 2KNO3(aq) In aqueous solutions (aq) the compounds are all dissociated into their constituent ions. The Comp[lete ionic equation shows all the ions present in solution seperately. Pb2+(aq) + 2NO3(-)(aq) + 2K+(aq) + 2I-(aq) --> PbI2(s) + 2K+(aq) + 2NO3(-)(aq) When you look at the abouve equation you can see that the 2NO3(-)(aq) and the 2K+(aq) are the same on both sides of the equation. This means they are not participating in the reaction, they are spectator ions. The NET ionic equation shows only those species in a reaction that are actually reacting. The spectator ions are left out. NET ionic equation Pb2+(aq) + 2I-(aq) = PbI2(s)

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