Urea (NH2CONH2) an important nitrogen fertilizer is produced industrially by the

Question

Urea (NH2CONH2) an important nitrogen fertilizer is produced industrially by the reaction

given that ?G initial = -13.6KJ, calculate ?G at 298K for the following sets of conditions

1) 20atm NH3, 20atm CO2, 5.0 M NH2CONH2

2) 5.0x10^-2 atm NH3, 5.0x10^-2 atm CO2, 1.0M NH2CONH2

3)Is the reaction spontaneous for the conditions in part (a) and/or part (b)?

spontaneous for the conditions in part (a), nonspontaneous for the conditions in part (b)
nonspontaneous for the conditions in both parts
spontaneous for the conditions in both parts
spontaneous for the conditions in part (b), nonspontaneous for the conditions in part (a)

Explanation / Answer

sol in Q you only need to plug in 3 for the P of (NH2CONH2); that is given by the original problem statement so for A) Q=5M(NH2CONH2)/[40M(NH3)^2*20M(CO2)] the equation: G = -13.6*10^3 J + (8.314J/molK)(298.15K)(ln{Q}) lnQ = -9.968 so G comes out to be -38308J or -38.3kJ b should be the same just plug in the new numbers and as to whether it is spontaneous or not ill let you figure that out ans

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