(i)write the balanced equation for the reaction of aqueous Pb(CLO3) with aqueous

Question

(i)write the balanced equation for the reaction of aqueous Pb(CLO3) with aqueous NaI including phases .

(ii) what mass of precipitate will form if 1.50 L of concentrated Pb(CLO3) is mixed with

0.550 L of 0.230 M NaI ? assume the reaction goes to completion.

Explanation / Answer

Pb(ClO3)2 (aq) & 2 NaI (aq) --> PbI2 (s) & 2 NaClO3 (aq) find moles 0.550 L (0.230 mol / Litre) NaI = 0.1265 moles of NaI by the equation Pb(ClO3)2 (aq) & 2 NaI (aq) --> PbI2 (s) & 2 NaClO3 (aq) 0.1265 moles of NaI produces 1/2 as many moles of PbI2 = 0 06325moles PbI2 use molar mass to find grams: 0 06325 moles PbI2 ( 461.02 grams / mol PbI2) = 29.15grams of PbI2

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.