consider the reaction: FeO(s) + Fe(s) + O2(g) ---> Fe2O3 given FeO (s) has delta

Question

consider the reaction:
FeO(s) + Fe(s) + O2(g) ---> Fe2O3

given FeO (s) has delta H of -271.9(kj/mol), S of 60.75 (j/mol*K)
Fe(s) has delta H of 0 ,and S of 27.15
O2(g) has delta H of 0, and S of 205.0
Fe2O3(s) has delta H of -822.16 and S of 89.96

What is the temperature in Celcius which the reaction is nonspontaneous. Please work out.

Explanation / Answer

H-TS>0 for non spontanous reaction H=-822.16+271.9=-550.29*10^3 (10^3 is because H is given in KJ) s=89.96-(60.74+27.15+205)=-202.93 TS=H T=-550.29*10^3/(-202.93) =2711.72 K

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