A nuclear reaction involves the hypothetical element X, which has an atomic numb

Question

A nuclear reaction involves the hypothetical element X, which has an atomic number of 166, as a reactant. The 360X nuclide reacts with 5 neutrons yielding a nuclide of element Y along with, altogether, 2 beta particles, 5 neutrons, 3 alpha particles, 3 positrons, and 3 gamma rays. The number of neutrons in the nucleus of the resultant nuclide of Y would be:

Explanation / Answer

360 X 166 + 5n0 =====> aYb + 2 0e(-1) +5 (1 n 0 ) + 3 (0 e 1) + 3 ( 4 He 2) + 3 gamma now 360 + 5 = a+0+5+0+(3*4)+0 a=365-(17)=343 and 166+0 = b+(-2*1)+(5*0)+(3*1)+(3*2)+0 b=166-(7) = 159 so the new element Y is 343 Y 159 now 343 is the mass number and 159 is the atomic number atomic number = number of protons Mass number = number of protons + number of neutrons Number of neutrons = Mass number- number of protons=343-159 = 184

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.