In questions 29-32 you are given lac operon genotypes. Use the following choices

Question

In questions 29-32 you are given lac operon genotypes. Use the following choices for each question. I^+ P^+ O^+ Z^+/I^+ P^+ O^+ Z^+ I^s P^+ O^+ Z^+/I^+ P^+ O^+ Z^+ I^+ P^+ O^C Z^+/I^+ P^+ O^+ Z^+ I^S P^+ O^+ Z^+/I^+ P^+ O^C Z^+ A deletion of the CAP-cAMP binding site in the lac operon would result in A nonsense mutation in the steroid hormone receptor protein gene would result in which of the following? For Questions 35-40 determine whether B-galactosidase, the product of the LacZ gene, will be produced Assume there is no available glucose. I^+ P^+ O^+ Z^+ in the presence of lactose I^+ P^+ O^+ Z^+ in the absence of lactose I^+ P^+ O^+ Z^+/I^+ P^+ O^C Z^+ in the presence of lactose I^S P^+ O^+ Z^+/I^+ P^+ O^+ Z^+ in the absence of lactose I^+ P^+ O^+ Z^+/I^+ P^+ O^C Z^+ in the absence of lactose I^+ P^+ O^+ Z^+/I^+P^+ O^C Z^+ in the presence of lactose

Explanation / Answer

33. Option C is answer.

CAP-cAMP bind to DNA and promote tight binding of RNA polymerase to the promoter. This make the transcription continous. But if its absent, RNA polymerase will not bind efficiently to the promoter.

34. Option B is the answer.

Since it is non sense mutation in hormone receptor, it means receptor protein is not formed completely. Due to nonsense mutation, there is STOP codon in the protein. Truncated protein is formed. This means there is no receptor for the hormone to take to the nucleus. And thus no activation of HRE and no transcription.

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