Determine the Free Energy Change for the following reaction at room temperature:

Question

Determine the Free Energy Change for the following reaction at room temperature:

2NO(g) + O2(g) => 2NO2(g)



1. -125.1 kiloJoules for that reaction

2. -111.4 kiloJoules for that reaction

3. -105.3 kiloJoules for that reaction

4. -93.2 kiloJoules for that reaction

5. -70.7 kiloJoules for that reaction

Explanation / Answer

The reaction you have is: 2 NO + O2 -> 2 NO2 1/2 N2(g) + O2(g) --> NO2(g), chnge in H = 33.2 kJ (should be multiplied by 2) N2 + 2 O2 -> 2 NO2.........change in H = +66,4 kJ 1/2 N2(g) + 1/2O2(g) --> NO(g), chnge in H = 90.2 kJ (should be multiplied by 2 and inverted) 2 NO -> N2 + O2..............change in H = -180,4 kJ Now you have: N2 + 2 O2 -> 2 NO2.........change in H = +66,4 kJ 2 NO -> N2 + O2..............change in H = -180,4 kJ --------------------------------------… canceling both N2 and 2 O2 with O2, you will find the given reaction: 2 NO + O2 -> 2 NO2........deltaH = 66,4 - 180,4 = -111.14 kJ so b)111.14

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