Our power plant generates electricity using a steam turbine. At the exit from ou
ID: 718059 • Letter: O
Question
Our power plant generates electricity using a steam turbine. At the exit from our power generation process, we end up with 978.0 kg/s of liquid water at 323.0 K. We cannot release this water directly into a nearby river if the temperature is over 305.00 K, without causing significant thermal pollution that would damage fish populations. Our plan is to mix this warm water with another cooler water stream at 282.00 K. What is the mass flow rate of this cool water stream needed to meet the regulation? Assume the heat capacity for all streams is 4.184 J/gK. 123Warm Water fromTurbineCoolWaterWater to RiverMixer (HINT: |X| is near an order of magnitude of 102 kg/s ).Our power plant generates electricity using a steam turbine. At the exit from our power generation process, we end up with 978.0 kg/s of liquid water at 323.0 K. We cannot release this water directly into a nearby river if the temperature is over 305.00 K, without causing significant thermal pollution that would damage fish populations. Our plan is to mix this warm water with another cooler water stream at 282.00 K. What is the mass flow rate of this cool water stream needed to meet the regulation? Assume the heat capacity for all streams is 4.184 J/gK. 123Warm Water fromTurbineCoolWaterWater to RiverMixer (HINT: |X| is near an order of magnitude of 102 kg/s ).
Our power plant generates electricity using a steam turbine. At the exit from our power generation process, we end up with 978.0 kg/s of liquid water at 323.0 K. We cannot release this water directly into a nearby river if the temperature is over 305.00 K, without causing significant thermal pollution that would damage fish populations. Our plan is to mix this warm water with another cooler water stream at 282.00 K. What is the mass flow rate of this cool water stream needed to meet the regulation? Assume the heat capacity for all streams is 4.184 J/gK. 123Warm Water fromTurbineCoolWaterWater to RiverMixer (HINT: |X| is near an order of magnitude of 102 kg/s ). 123Warm Water fromTurbineCoolWaterWater to RiverMixer Water fromTurbineCoolWaterWater to RiverMixer (HINT: |X| is near an order of magnitude of 102 kg/s ).
Explanation / Answer
Mass of hot water mh = 978 kg/s
Specific heat capacity of hot water Cph = 4.184 J/gK
Initial temperature of hot water Th1 = 323 K
Final temperature of hot water Th2 = 305 K
Mass of cold water mc =?
Specific heat capacity of cold water Cpc = 4.184 J/gK
Initial temperature of cold water Tc1 = 282 K
Final temperature of cold water Tc2 = 305 K
Energy released by hot water = energy absorbed by cold water
mh x Cph x (Th1 - Th2) = mc x Cpc x (Tc2 - Tc1)
978 kg/s x 4.184 J/gK x (323 - 305)K = mc x 4.184 J/gK x (305 - 282)K
17604 = mc x 23
mc = 765.39 kg/s
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.