2. The population of a city is 100,000. The weighted equivalent diameter of the

Question

2. The population of a city is 100,000. The weighted equivalent diameter of the sewers is 20 cm. Calculate the total /I per day that may reach the wastewater treatment plant if the VI allowance is 1400L per day per cm per km. Average sewerage length per capita is 8m. 3. Determine ThoD, COD, and BODs of a mixture of 150 mg/L glutamic acid (CsHioN O,) and 150 mg/L glucose (CHi). Assume the value of the BOD first-order reaction rate constant is 0.23/d (base e) and only carbonaceous oxygen demand is considered.

Explanation / Answer

Ans 2

Population P = 100,000

Equivalent sewer dia D = 20 cm

Total sewerage length = (8 m / person) x P

= 8 x 100,000 = 800,000 m x 1km/1000m

L = 800 km

Total I/I per day = 1400 L/(day - cm - km) x D x L

= 1400 L/(day - cm - km) x 20cm x 800 km

= 22400000 L/day

= 2.24*10^7 L/day

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