Q3. Oil (sg of 0.8) and mercury (s g. of 13.6) each fills half of a cylindrical
ID: 717955 • Letter: Q
Question
Q3. Oil (sg of 0.8) and mercury (s g. of 13.6) each fills half of a cylindrical storage tank. The height of the tank is 400 cm and it is completely filled. The tank's top cover is open. What is the pressure at the bottom of the tank in terms of head of water? (15 points) 04. NJIT ME students intend to design a submersible that can withstand a gauge pressure equivalent to 10 m mercury (s.g. of 13.6). At what depth in the ocean would the submersible fail (density of ocean water: 1040 kg/m? (15 points)Explanation / Answer
Ans 3
Pressure at bottom = Patm + pressure due to oil + pressure due to mercury
= 101325 Pa + density of oil x g x (h/2) + density of mercury x g x (h/2)
= [101325 Pa] + [0.80*1000 kg/m3 x 9.81 m/s2 x (400 cm x 1m/100cm) / 2] + [13.6*1000 kg/m3 x 9.81 m/s2 x (400 cm x 1m/100cm) / 2 ]
= 101325 Pa + 15696 Pa + 266832 Pa
P = 383853 Pa
In terms of head of water
P = 383853 Pa x ( 1 m H2O / 9806.38 Pa)
= 39.14 m H2O
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