if your front lawn is 19.0 feet wide and 20.0 feet long, and each square foot of

Question

if your front lawn is 19.0 feet wide and 20.0 feet long, and each square foot of lawn accumulated 1150 new snow flakes every minute, how much snow (in kilograms) accumulated in your lawn per hour? Assume an average snow flake has a mass of 1.60 mg if your front lawn is 19.0 feet wide and 20.0 feet long, and each square foot of lawn accumulated 1150 new snow flakes every minute, how much snow (in kilograms) accumulated in your lawn per hour? Assume an average snow flake has a mass of 1.60 mg if your front lawn is 19.0 feet wide and 20.0 feet long, and each square foot of lawn accumulated 1150 new snow flakes every minute, how much snow (in kilograms) accumulated in your lawn per hour? Assume an average snow flake has a mass of 1.60 mg

Explanation / Answer

Area of the Lawn= Width x Length = 19 x 20 = 380 square foot.

Now, Each square foot of lawn accumulated 1150 new snow flakes every minute,

Therefore, 380 square foot of lawn will accumulate 1150 x 380 = 437,000 snow flakes Per minute.

And, 380 square foot of lawn will accumulate 437000 x 60 = 26,230,000 snow flakes Per hour. ( As 1 hour= 60 minutes)

Now, mass of one snow flake = 1.60 mg.

Thus, mass of 26,230,000 snow flakes will be = 26,230,000 x 1.60 mg

= 41,952,000 mg.

Now, as 1 mg = 1/103 g

Thus, Mass of snow flakes Per hour (in grams) = 41,952 g.

As, 1Kg= 1000 grams, so mass is snow flakes Per hour (in Kg) = 41.952 Kg

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