Data Table #2: Total Ag95 Sample Water volume (ul ye- Tube Sample Reagent Volume
ID: 717430 • Letter: D
Question
Data Table #2: Total Ag95 Sample Water volume (ul ye- Tube Sample Reagent Volume Volume 11 Unknown BSA undiluted 12 Unknown BSA 1:5 dilution 13 Unknown BSA 1:25 dilution 14 Unknown BSA 1:125 dilution 15 BSA (1 mg/ml 16 Lysozyme (l mg/ml 17 Gelatin (1 mg/ml 18 Water t water 19 BSA (l mg/ml) + water 20Water + 1M NaCl 21BSA (1 mg/ml) + 1M 22 | Water +1%SDS 23 | BSA (1 mg/ml)-1%SDS 24 Water + +0.05M BME 25BSA (1 mg/ml) +0.05M BME 26Water + 0.25mg/ml RNA 27 BSA (l mg/ml) + 0.25mg/ml RNA 50+150 100 100 100 100 50 50 50 50+150 50+150 50+150 50+150 50+150 50+150 50+150 50+150 50+150 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 1500 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000 3000Explanation / Answer
Solution :-
Following are the calculations of the concnetration of each component of the given tube at the final volume when two components are mixed. Dilution formula used to calculate the final concentration.
Tube 21
Initial volume of NaCl V1 = 150 uL
Initial concentration of NaCl = 1 M *1000 mM/1M = 1000 mM
Final volume V2 = 50+150 = 200 uL
C1V1=C2V2
C2=C1V1/V2
= 1000 mM*50uL/200 uL
= 250 mM NaCl
Tube 23
V1= 150 uL
C1= 1%
V2 = 50+150 = 200 uL
C2=?
C1V1=C2V2
C2=C1V1/V2
= 1 % *150 uL /200 uL
= 0.75 % SDS
Tube 25
V1=150 uL
C1=0.05 M
C2=?
V2 = 50+150 = 200 uL
C1V1=C2V2
C2=C1V1/V2
= 0.05 M*150 uL/ 200 uL
= 0.0375 M
Converting M to mM
0.0375 M* 1000 mM / 1 M = 37.5 mM BME
Tube 27
C1=0.25 mg/ml RNA
V1= 150 uL
C2=?
V2 = 50+150 = 200 uL
C1V1=C2V2
C2=C1V1/V2
= 0.25 mg/mL RNA * 150 uL / 200 uL
= 0.188 mg/mL RNA
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