I\'m having trouble understanding how to determine the highest boiling point. no

Question

I'm having trouble understanding how to determine the highest boiling point.

now.com/urn tas 2req Use the References to access important values if needed for this question. Match the following aqueous solutions with the appropriate letter from the column on the right 1. 0.14 m MnCl2 2. 0.16 m (NH42CO3 3. 0.17 m CaCl2 4. 0.44 m Ethylene glycoknonelectrolyte) D. Lowest boiling point A. Highest boiling point B. Second highest boiling point C. Third highest boiling point s 2req s 2req Retry Entire Group 7 more group attempts remaining Submit Answer

Explanation / Answer

Answer:

We know that boiling point elevation,

Tb=i x Kb x m

Where i=Van'thoff factor (for NaCl---> Na^+ + Cl^-, then i=2) Kb=boiling point constant, m=molality.

(1) 0.14 m MgCl2.

MgCl2 -----> Mg^+2 + 2Cl^- then i=3.

Therefore Tb=Kb x 3 x 0.14 =0.42 Kb.

(2) 0.16 m (NH4)2CO3,

i=3 ((NH4)2CO3 ----> 2NH4^+ + CO3^2-)

Tb=Kb x 3 x 0.16 =0.48 Kb.

(3) 0.17 m CaCl2

i=3 for CaCl2 ----> Ca^+2 + 2Cl^-

Tb=Kb x 3 x 0.17=0.51 Kb.

(4) 0.44 m ethylene glycol

Since ethylene glycol is non electrolyte, so i=1.

Therefore Tb=Kb x 1 x 0.44=0.44 Kb.

So the order of boiling point is

0.17 m CaCl2 > 0.16 m (NH4)2CO3 > 0.44 m ethylene glycol > 0.14 m MnCl2.

(3) ------ (A)

(2) ------ (B)

(4) ------ (C)

(1) ------- (D)

Please let me know if you have any doubt. Thanks.

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