Exercise 3.2. At a certain temperature, the equilibrium constant Kp for the gas-
ID: 715881 • Letter: E
Question
Exercise 3.2. At a certain temperature, the equilibrium constant Kp for the gas-phase reaction CO(g) + Br2(g)COBr2(g) is 0.0250. Suppose a 9:4 (in terms of partial pressures) reaction mixture of CO and Br2 is heated in a closed vessel at a total pressure of 19.5 bar. Using the final notebook from Example 3.1 as a template, create a Mathematica notebook to calculate the equilibrium partial pressures (in bar) of all three gases: (a) CO, (b) Br2, (c) COBr2, (d) perform the check for Kp, and (e) calculate the percentage of Br2(g) that will be converted to COBr2(g) under these conditions. Save the notebook as "Exercise_3.2.nb". Warning! All calculation steps must be performed in your Mathematica notebook, and all items (a-e) must be clearly labelled in the Print] functions, or the score for this exercise will be zero! Hint: https://en.wikipedia.org/wiki/Partial pressure Answers: (a) 12.1 bar (b) 4.61 bar (c) 1.39 bar (d)(e)Explanation / Answer
we had 9 :4 ratio of CO and Br2
let X part of CO and BR2 combine to form COBR2
hence pCO = 9-X , pBr2 = 4-X , pCOBr2 = X
Kp = pCOBr2 / ( pCO) ( pBr2)
0.025 = (X) / ( 9-X ) ( 4-X)
0.025 ( 9-X) ( 4-X) = X
( X^2 -13X + 36) = X / 0.025
X^2 -53X + 36 = 0
X = 0.688
Br2 % converted = ( 100 ) x ( X / initial Br2 amount)
= ( 100 x 0.688 /4) = 17.2 %
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