There are three sets of sketches below, showing the same pure molecular compound
ID: 715534 • Letter: T
Question
There are three sets of sketches below, showing the same pure molecular compound (sulfur dioxide, molecular formula SO2) at three different temperatures The sketches are drawn as if a sample of sulfur dioxide were under a microscope so powerful that individual atoms could be seen. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: melting point of SO2:-72.0 °C boiling point of SO2: 10.0 °c 333399 . 3000% | 1 2 3 45 1 2 3 4 5 -94.°C 1 2 34 5 07. CExplanation / Answer
Melting point of SO2 = -72oC
Boiling point of SO2 = -10oC
In the above B diagram we can see that there are 2 red shaped molecules and 1 yellow molecule, together it would be SO2
I.e 2 red are oxygen atoms and 1 yellow is sulphur.
In between melting point and boiling point molecules will be in liquid state and above boiling point the SO2 molecules be in gaseous state.
SO2 molecule should contain 3 atoms among then in the above picture 2 red atoms would be oxygen and 1 yellow atom would be sulphur.
In the above 3 A,B and C images A is at 107oC i.e above the boiling point so SO2 should be in gaseous state where molecules should move freely and rapidly than in liquid state
In image B which is at -94oC i.e just below the melting point so the SO2 should be in solid state where molecules are regularly and uniformly arranged.
In image C which is at -17oC i.e just below boiling point so the SO2 should be in liquid state where molecules move freely than in solid state
Based on above characteristics, we need the slide the images from 1 to 5 and check whether at what point they are behaving in the above characteristic properties.
In the above images
A : 1 sulphur and 2 oxygen atoms are dissociated in gaseous state
B : SO2 molecules are arranged in regular ordered manner so this would be the answer.
C : the sulphur and oxygen atoms are completely dissociated.
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