Don’t know if I did #6 right 0 Evaluation of Rate Constant,k 2 The reaction orde

Question

Don’t know if I did #6 right 0 Evaluation of Rate Constant,k 2 The reaction order.m, with respect to oystal voiler CV/is 3. The slope, and therefore saude rate canstant ka' s at Ti 4. Explain your answers in 02 &3 5 Since, for Kinetic Run I, you mixed 1.00 mL of 0.020M NaOH and 9.00 ml of crystal violet solution, use the dilution equation to calculate the initial molarity of Na0H ie. once it was in solution but at t 0(or before reaction started). Do the same calculation for Kinetic Run I where you mixed 1.00 mL of Q.10 M NaOH and 9.00 mL of crystal violet solution m,(.oomL(o2om NoHLoe (4.00mL) 2Mo)G.oem (a.oont NaOH: 002 M 6. Use the equation we derived on page 3 (Eqn 3), to calculate the true rate constont k,at each temperature Knetic Run kk/101 (Eqn 3) ks kino Ms True rate: kr012 12

Explanation / Answer

6.Wrong

Because u need to take the initial concentration of NaOH as 0.012M in kinetic Run I and 0.01M in kinetic Run II

Kinetic Run I

K=k'/[OH-]

= 2.4×10-4/0.00

= 0.12Ms-

Kinetic Run II

K= k"/[OH-]

=1.38×10--3/0.01

= 0.138Ms-

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